Final answer:
The given function F(s) is solved for f(t) by applying the inverse Laplace transform. The result is f(t) = 67.5t^2e^(-3t)u(t), which is a non-oscillatory function without a phase angle in radians.
Step-by-step explanation:
To find the function f(t) for the given F(s) which is 135/(s+3)³, we need to apply the inverse Laplace transform. The inverse Laplace transform of 1/s^n is t^(n-1)/(n-1)! multiplied by the unit step function u(t). In our case, n equals 3.
Therefore, the inverse Laplace transform of 135/(s+3)³ is:
f(t) = 135 * t^(3-1)/(3-1)! * e^(-3t) * u(t)
f(t) = 135/2 * t^2 * e^(-3t) * u(t)
Expressed using radians, there is no phase angle in this function because it is not an oscillatory function.
Hence, f(t) = 67.5t^2e^(-3t)u(t)