Final answer:
To perform the operation ∫(2 x VA - VB) in a circuit, one would use two operational amplifiers, with the first acting as an integrator for the voltage VA and the second configured to subtract the voltage VB, resulting in the output Vout measured at the second op-amp's output.
Step-by-step explanation:
To create a circuit that can perform the operation ∫(2 x VA - VB), an operational amplifier (op-amp) configured as an integrator can be used. In this case, VA and VB are the inputs from two voltage sources. The general approach would involve:
Connecting the non-inverting input of the first op-amp to ground to create a virtual ground reference point.
Feeding the voltage VA through a resistor to the inverting input of the first op-amp.
Configuring the first op-amp with a feedback capacitor to perform the integration of the voltage VA.
Using a second op-amp to subtract the voltage VB, which is similarly passed through a resistor to its inverting input, with the output of the first op-amp connected to the non-inverting input of the second op-amp.
The output voltage Vout, which represents the integrated voltage ∫(2 x VA - VB), will be measured at the output of the second op-amp. By properly selecting the resistors and capacitors, the desired operation can be achieved. This output can be measured using a voltmeter, connected across the output terminal of the second op-amp and the ground.