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An industrial load consisting of a bank of induction motors consumes 150 kW at a power factor of 0.9 lagging from a 220−V,60−Hz, single-phase source. By placing a bank of capacitors in parallel with the load, the resultant power factor is to be raised to 0.95 lagging. Find the net capacitance of the capacitor bank in μF that is required.

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Final answer:

To raise the power factor, a capacitor should be placed in parallel with the load. The formula Ct = P x tan(theta) / (2 x pi x f x V^2) can be used to calculate the net capacitance required.

Step-by-step explanation:

To raise the power factor of the circuit, a capacitor should be placed in parallel with the load. The formula to calculate the net capacitance (Ct) required can be derived from the formula:

Ct = P x tan(theta) / (2 x pi x f x V^2)

Where P is the power consumed by the load, theta is the angle between the original and desired power factors, f is the frequency, and V is the voltage.

Using the given values, the net capacitance required can be calculated as follows:

Ct = 150 kW x tan(arccos(0.9) - arccos(0.95)) / (2 x pi x 60 Hz x (220 V)^2)

User Steven De Groote
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