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Subtract: (3b-2c)-(6c+2b)-(b+c)

User Marzouk
by
7.8k points

2 Answers

6 votes

Answer:-9c

Step-by-step explanation:

First arrange

(3b-2c)-(6c+2b)-(b+c) into

(3b-2c)-(2b+6c)-(b+c)

Release brackets

3b-2c-2b+6c-(b+c)

For (b+c), once you release the bracket, the addition sign(+) will turn into a subtraction(-) sign. Which is b-c

3b-2c-2b+6c-b-c

Then do subtraction

3b-2c-2b+6c-b-c

3b-2b-b=0b

With nothing left, do the c.

-2c-6c-c=-9c

Therefore, the answer is -9c

:)

User Nass
by
7.6k points
3 votes

Final answer:

To subtract the given expression, distribute the negative sign, combine like terms, and simplify.

Step-by-step explanation:

To subtract the given expression:

  1. Distribute the negative sign to each term within the parentheses, resulting in:
  2. 3b-2c-6c-2b-b-c
  3. Combine like terms:
  4. (3b-2b)-(2c+6c)-(b+c)
  5. b-8c-2b-c
  6. Combine like terms again:
  7. (b-2b)-(8c-c)
  8. -b-7c
  9. Therefore, the simplified expression is -b-7c.
User Velis
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6.3k points