Final answer:
The hot metal object that will raise the water's temperature more is the one with greater mass and lower specific heat capacity. Heat transfer amount depends on calorimetry principles, where water typically has a higher specific heat capacity than many substances, resulting in smaller temperature changes for a given amount of heat transfer.
Step-by-step explanation:
When considering which of two hot metal objects will raise the temperature of water more, we need to think about heat transfer, specifically the concept of calorimetry. Both have the same initial temperature, but the amount of heat transferred will depend on each metal's mass, specific heat capacity, and any energy losses due to the environment. The object with the greater mass and lower specific heat capacity will transfer more heat to the water, assuming no heat is lost to the surroundings. In a calorimetry problem like the ones mentioned, the scenario involves two bodies at different temperatures coming into contact and exchanging heat until thermal equilibrium is reached. The specific heat capacity plays a crucial role here—it's the amount of heat per unit mass required to raise the temperature by one degree Celsius. Higher specific heat indicates that the substance will absorb more heat for a given temperature change. If we consider the example provided, where metal is put into water and both reach thermal equilibrium, the final temperature will not be the average of the two initial temperatures. Instead, it will be much closer to the initial temperature of the water because water has a greater specific heat than most common substances. This means that water will undergo a smaller temperature change for a given heat transfer.