Given:
2x + y + z=2 .... (1)
4x +2y +2z=4 .... (2)
-6x -3y -3z =-6.... (3)
Taking Equation (3)
-6x-3y-3z=-6
Divide by -3,
2x+y+z=2 ....(4)
By subracting equation (2) and (4),
0=0
Therefore, the system of equation has infinitely many solution.
Option B is the correct answer.