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A beam of light enters the flat surface of a diamond from air (n = 1.00) at an angle of 30° from the normal. The angle of refraction in the diamond is measured to be 12° from the normal. Determine the index of refraction for the diamond ?

User Fillet
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Final answer:

Using Snell's law, the index of refraction for the diamond is calculated as approximately 2.404, when light enters the diamond from air with an incidence angle of 30° and a refraction angle of 12°.

Step-by-step explanation:

To determine the index of refraction for the diamond when a beam of light enters from air at an angle of 30° from the normal and the angle of refraction is 12°, we can use Snell's law. This law relates the angles of incidence and refraction to the indices of refraction for the two media through which the light is traveling:

n1 * sin(θ1) = n2 * sin(θ2)

Here, n1 is the index of refraction of air which is 1.00, θ1 (theta1) is the angle of incidence which is 30°, n2 is the index of refraction of diamond which we wish to find, and θ2 (theta2) is the angle of refraction which is 12°. Plugging in the values we have, we can rearrange the formula to solve for n2:

n2 = n1 * sin(θ1) / sin(θ2)

Substitute the known values:

n2 = 1.00 * sin(30°) / sin(12°)

n2 = 1.00 * 0.5 / 0.2079

n2 = 2.404

Therefore, the index of refraction for the diamond is approximately 2.404.

User Davegaeddert
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