Question

A stone is thrown at an angle of 30 above the horizontal from the top edge of a cliff with an initial speed of 12 m/s². A stopwatch measures the stone's trajectory time from the top of the cliff to bottom to be 5.6 s. What is the height of the cliff?

a) 154 m
b) 58 m
c) 120
d) 197 m

Answer 1

The height of the cliff is approximately B) 58 m.

Step-by-step explanation:

To calculate the height of the cliff, we can use the equation:

h = (v02sin2(θ)) / (2g)

where h is the height of the cliff, v0 is the initial velocity of the stone, θ is the angle of projection, and g is the acceleration due to gravity.

Plugging in the given values:

h = (122sin2(30)) / (2*9.8)

h ≈ 58 m

Therefore, the height of the cliff is approximately 58 m.