Question

10a + 6b + 6cIt needs to be simplified I also need the steps

Answer 1

Since all the numbers that accompany the letters a, b and c are even, then you can apply common-factor to factor the 2.

Then you have

`\begin{gathered} 10a+6b+6c=2\cdot5a+2\cdot3b+2\cdot3c \\ 10a+6b+6c=2(5a+3b+3c) \end{gathered}`

Therefore, the given simplified expression is

`2(5a+3b+3c)`