Question

A circular loop of wire with a diameter of 21.475 cm is in the horizontal plane and carries a current of 3.917 A counterclockwise, as viewed from above. What is the magnetic field, in microTeslas, at the center of the loop?

Answer 1

Given:

The diameter of the circular loop is: d = 2r = 21.475 cm.

The current in the wire is: I = 3.917 A.

To find:

The magnetic field at the center of the loop.

Step-by-step explanation:

The magnetic field at the center of the circular loop is:

`B=(\mu_0I)/(2r)=\frac{4\pi*10^(-7)\text{ T.m/A}*3.917\text{ A}}{21.475*10^(-2)\text{ m}}=2.2920*10^(-5)\text{ T}=22.92*10^(-6)\text{ T}=22.92\text{ }\mu T`

Final answer:

The magnetic field at the center of the circular loop is 22.92 micro Tesla.