Question

4) P(x; y) = 3x² + 5y-x³y³ para x=2, y=3​

Answer 1

The value of P(x; y) when x = 2 and y = 3 is -189.

Step-by-step explanation:

The given equation is P(x; y) = 3x² + 5y - x³y³. We are asked to evaluate P(x; y) for x = 2 and y = 3.

Substituting the values x = 2 and y = 3 into the equation, we get:

P(2; 3) = 3(2)² + 5(3) - (2)³(3)³

P(2; 3) = 3(4) + 15 - 8(27)

P(2; 3) = 12 + 15 - 216

P(2; 3) = -189

Therefore, when x = 2 and y = 3, the value of P(x; y) is -189.