Question

When 49.5 J of heat was transferred to 7.3 g of iron at 22 degrees Celsius, the temperature of the iron increases to 37 degrees Celsius. What is the specific heat of iron in J/g/C?

Answer 1

The specific heat of iron, given that 49.5 J of heat raises the temperature of a 7.3 g sample from 22°C to 37°C, is calculated to be 0.452 J/g°C.

Step-by-step explanation:

The specific heat of iron can be calculated using the formula q = mcΔT, where q is the amount of heat transfer, m is the mass of the sample, and ΔT is the change in temperature. In this case, the temperature change (ΔT) is the final temperature (37 degrees Celsius) minus the initial temperature (22 degrees Celsius), hence ΔT = 37°C - 22°C = 15°C. The mass (m) of the iron is given as 7.3 g, and the heat transfer (q) is 49.5 J.

Using the formula and substituting the known values in:

q = mcΔT

49.5 J = (7.3 g)c(15°C)

We can solve for the specific heat (c) of the iron:

c = 49.5 J / (7.3 g × 15°C)

c = 49.5 J / 109.5 g°C

c = 0.452 J/g°C

Therefore, the specific heat of iron is 0.452 J/g°C.