Question

Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)

Answer 1

Potential difference
`V=1.6* 10^(-10)\ V`

Step-by-step explanation:

Capacitance of capacitor, C = 0.9 MF

Charge,
`Q=1.4* 10^(-4)\ C`

We need to find the amount of potential difference. We know that,

`Q=CV`

V is potential difference

So,

`V=(Q)/(C)\\\\V=(1.4* 10^(-4))/(0.9* 10^6)\\\\V=1.6* 10^(-10)\ V`

So, the required potential difference is
`1.6* 10^(-10)\ V`.