Question

A woman's obstetric history indicates that she is pregnant for the fourth time, and all of her children from previous pregnancies are living. One was born at 39 weeks of gestation, twins were born at 34 weeks of gestation, and another child was born at 35 weeks of gestation. What is her gravidity and parity using the GTPAL system?

1) 3-1-1-1-3
2) 4-1-2-0-4
3) 3-0-3-0-3
4) 4-2-1-0-3

Answer 1

The woman's obstetric history using the GTPAL system is 4-1-2-0-3, indicating she is pregnant for the fourth time (gravidity), has had one full-term birth, two preterm births (which include twins), no abortions, and has three living children.

Step-by-step explanation:

GTPAL System Explanation

The GTPAL system is used in obstetrics to detail a woman’s pregnancy and childbirth history. It stands for Gravidity, Term births, Preterm births, Abortions, and Living children. In the scenario provided, the pregnant woman is pregnant for the fourth time, which indicates her gravidity is 4. She has had one full-term birth at 39 weeks, preterm twins at 34 weeks, and another preterm birth at 35 weeks. Regarding parity, she has not had any abortions, which makes this number zero. All her children from these pregnancies are living, thus, the number of living children is three.

Therefore, her obstetric history using the GTPAL system would be:

• Gravidity (G): 4 (This is her fourth pregnancy.)
• Term births (T): 1 (One child was born at full term.)
• Preterm births (P): 2 (The twins plus one more child were born at preterm.)
• Abortions (A): 0 (She has had no miscarriages or elective abortions.)
• Living children (L): 3 (All of her children are living.)

The correct answer to her GTPAL is 4-1-2-0-3, which corresponds to the second option provided.