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At noon, ship A is 170 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 20 km/h. How fast (in km/hr) is the distance between the ships changing at 4:00 p.m.? (Round your answer to three decimal places.)

User Baek
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Final answer:

The distance between the ships is changing at a rate of approximately 6.522 km/h at 4:00 p.m.

Step-by-step explanation:

To find the speed at which the distance between the ships is changing, we can use the concept of relative motion. At 4:00 p.m., 4 hours after noon, ship A would have traveled 120 km (30 km/h x 4 hours) to the east. Ship B, on the other hand, would have traveled 80 km (20 km/h x 4 hours) to the north. Using the Pythagorean theorem, we can calculate the distance between the two ships at 4:00 p.m. as follows:

D = sqrt((170 km + 120 km)^2 + (0 km + 80 km)^2)

= sqrt(57500) km

≈ 239.802 km

To find how fast this distance is changing, we can take the derivative of the distance equation with respect to time:

dD/dt = ((170 km + 120 km)(30 km/h) + (0 km + 80 km)(20 km/h))/(sqrt(57500) km)

Simplifying this expression gives us:

dD/dt ≈ 6.522 km/h

Therefore, the distance between the ships is changing at a rate of approximately 6.522 km/h at 4:00 p.m.

User Luke Woodward
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