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39 votes
39 votes
R's sleep log: 8.5 8 9.5 9 7.5 8.5B's sleep log 6.5 7 7.5 6.5 12 7.5which statement is NOT true about the data provided?a. both sets of data have an interquartile range of 1b. both measures of center for R's data have a value of 8.5c. the shape of both data distributions are non-symmetricd. the IQR of B's data is best used to describe the spread because of the outlierR's sleep log: 8.5 8 9.5 9 7.5 8.5B's sleep log 6.5 7 7.5 6.5 12 7.5

User Juan Velez
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1 Answer

15 votes
15 votes

Answer

C. The shape of both data distributions are non-symmetric

Explanation

Ordering both data sets from least to greatest, we get:

R's sleep log:7.5 8 8.58.5 99.5

B's sleep log: 6.5 6.577.57.512

We can see that B's data is concentrated at the lower values (12, the maximum, is an outlier). Then, the shape of B's data distribution is non-symmetric. But, in R's data every value is equidistant from the other ones, in consequence, the shape of R's data distribution is symmetric.

User Keif Kraken
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