Question

Please answer!
Find the lengths of the segments with variable expressions.

Answer 1

EF = 8

Explanation:

The midsegment EF is half the sum of the parallel bases , that is

x =
`(x-5+2x-3)/(2)` ( multiply both sides by 2 to clear the fraction )

2x = 3x - 8 ( subtract 2x from both sides )

0 = x - 8 ( add 8 to both sides )

8 = x

Thus

EF = x = 8

AD = x - 5 = 8 - 5 = 3

BC = 2x - 3 = 2(8) - 3 = 16 - 3 = 13