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What is the mass, in grams, of 2.74 L of CO gas measured at 33 degrees C and 945 mmHg?

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Final answer:

To find the mass of 2.74 L of CO gas, first convert the volume to moles using the ideal gas law equation. Then calculate the number of moles and find the mass using the molar mass of CO gas.

Step-by-step explanation:

To find the mass of 2.74 L of CO gas, we first need to convert the volume of gas to moles using the ideal gas law equation. The ideal gas law equation is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin. To do this, we add 273 to the temperature in Celsius. So, 33 degrees Celsius is equivalent to 33 + 273 = 306 Kelvin.

Next, we convert the pressure from mmHg to atm. 1 atm is equal to 760 mmHg, so the pressure of 945 mmHg is equal to 945/760 = 1.242 atm.

Now we can use the ideal gas law equation to calculate the number of moles. Rearranging the equation to solve for n, we have n = PV/RT. Plugging in the values, we get n = (1.242 atm)(2.74 L)/(0.0821 L•atm/(mol•K))(306 K) = 0.126 moles. Finally, we can calculate the mass of CO gas using its molar mass, which is 28 grams/mole. Therefore, the mass of 2.74 L of CO gas is 0.126 moles * 28 grams/mole = 3.528 grams.

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