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A testing chamber holds a 2.50 L sample of neon gas at 325.0 K.If the pressure is measured inside the chamber as 4.00 atm, how many moles of neon are present?0.4530.44200.3750.326

User Ben DeMott
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1 Answer

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Answer: There are 0.375 moles of neon gas present in the testing chamber.

Step-by-step explanation:

The question requires us to calculate the number of moles of neon gas, given that the gas is in a 2.50 L chamber at 325.0 K and the pressure inside the chamber is 4.00 atm.

We can solve this problem using the equation for ideal gases, as shown below:


PV=nRT

where P is the pressure of the gas (P = 4.00 atm), V is the volume of the gas (V = 2.50 L), n is the number of moles, that we want to calculate, T is the temperature of the gas (T = 325.0 K) and R is the gas constant.

Note that the values of pressure and volume are given in atm and L, respectively. Therefore, we can apply the gas constant in units of L.atm/mol.K:

R = 0.082057 L.atm/K.mol

First, let's rearrange the equation of ideal gases in order to calculate the number of moles of gas:


PV=nRT\rightarrow n=(PV)/(RT)

Now, applying the values given by the question and the constant R, we'll have:


n=((4.00atm)*(2.50L))/((0.082057L.atm/K.mol)*(325.0K))=0.375mol

Therefore, there are 0.375 moles of neon gas in the testing chamber under the conditions given by the question.

User Goodwine
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