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Brewster applies a force of 10 N to one end of a cord to keep a bag of rubber frogs tied to the other end moving out of speed of 2 m a second and a horizontal circle of radius 3 m what is the mass of the bag of frogs

User Stansult
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1 Answer

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Final answer:

To find the mass of the bag of frogs, we use the equation Fc = (mv²)/r where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius. By substituting the given values, we can solve for the mass and determine that it is 7.5 kg.

Step-by-step explanation:

To find the mass of the bag of frogs, we can start by understanding the forces at play in this situation. Brewster applies a force of 10 N to keep the bag of frogs moving in a horizontal circle of radius 3 m. In circular motion, the centripetal force is given by the equation Fc = (mv²)/r, where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius. In this case, the centripetal force is provided by the force applied by Brewster. So, we have Fc = 10 N. The velocity is given as 2 m/s and the radius is 3 m. Substituting these values into the equation, we can solve for the mass:

Fc = (mv²)/r

10 N = (m * 2² m/s) / 3 m

10 N = 4m / 3

30 N = 4m

m = 7.5 kg

Therefore, the mass of the bag of rubber frogs is 7.5 kg.

User Dlamotte
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