Can you help with this one its has 11 part to it

Jerska asked Apr 2, 2023

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Jerska asked Apr 2, 2023

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Recall that the limit of a function exists if

$\lim_(x\to n^+)f(x)=\lim_(x^\to n^-)f(x).$

Now, from the graph, we get that:

$\begin{gathered} \lim_(x\to0^-)f(x)=0, \\ \lim_(x\to0^+)f(x)=0, \end{gathered}$

therefore:

$\lim_(x\to0)f(x)=0.$

Robertp answered Apr 9, 2023

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