Answer:
0.279 g He
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
4.20 × 10²² molecules He
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of He - 4.00 g/mol
Step 3: Convert
- Set up:
![\displaystyle 4.20 \cdot 10^(22) \ molecules \ He((1 \ mol \ He)/(6.022 \cdot 10^(23) \ molecules \ He))((4.00 \ g \ He)/(1 \ mol \ He))](https://img.qammunity.org/2022/formulas/chemistry/high-school/nrzyhub21n5rsg3u7b9du2pxxmzpe214xr.png)
- Multiply/Divide:
![\displaystyle 0.278997 \ g \ He](https://img.qammunity.org/2022/formulas/chemistry/high-school/vcsoma3xbkwrmglyskzs3t4wjf0rxy73el.png)
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.278997 g He ≈ 0.279 g He