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A 0.40 kg stone attached to a string moves at a constant speed of 4 meters per second in a horizontal circle having a radius of 0.80 meter. What is the magnitude of the stone's centripetal force?

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Final answer:

The magnitude of the stone's centripetal force is calculated using the formula Fc = mv²/r. Given the mass of 0.40 kg, velocity of 4 m/s, and radius of 0.80 m, the centripetal force is determined to be 6.4 Newtons.

Step-by-step explanation:

To determine the magnitude of the stone's centripetal force, we will use the formula for centripetal force, which is Fc = mv²/r, where m is the mass of the object, v is the velocity, and r is the radius of the circular path.

For the given values:
- The mass (m) of the stone is 0.40 kg.
- The constant speed (v) is 4 meters per second.
- The radius (r) of the horizontal circle is 0.80 meter.

Plugging these values into the formula, we get:
Fc = (0.40 kg)(4 m/s)² / 0.80 m
Fc = (0.40 kg)(16 m²/s²) / 0.80 m
Fc = 6.4 N

Therefore, the magnitude of the stone's centripetal force is 6.4 Newtons.

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