Question

A 3 kilogram block is initially at rest on a frictionless, horizontal surface. The block is moved 8 meters in 2 seconds by the application of a 12 N horizontal force. Calculate the power developed while moving the block?

1) 48 W
2) 32 W
3) 24 W
4) 96 W

Answer 1

The power developed while moving the block is calculated by dividing the work done (96 Joules) by the time taken (2 seconds), resulting in a power of 48 Watts.

Step-by-step explanation:

To calculate the power developed while moving the block, we use the formula for power, which is work done divided by the time taken. The work done is equal to the force multiplied by the displacement in the direction of the force. Since the block is moved horizontally by the force, and given that the force is also horizontal, the work done is simply:

Work = Force × Displacement = 12 N × 8 m = 96 Joules.

Now, dividing the work done by the time taken gives the power:

Power = Work / Time = 96 J / 2 s = 48 W.

Therefore, the correct answer is 48 W, which corresponds to option 1).