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How many molecules are present in 0.93 grams of Fe2O3?
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How many molecules are present in 0.93 grams of Fe2O3?

User Fpanizza
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Answer:

5.8125*10^-3

the moles in Fe2O3 are 0.93/(56*2 + 16*3) = 5.8125*10^-3

User Blakes Seven
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