Question

9. I have a pressure of 65 kPa and a starting temperature of29°C. If I raise the temperature to 167°C, what is the newpressure?

Answer 1

`94.70\text{ kPa}`

Step-by-step explanation:

Here, we want to get the new pressure

According to the pressure law, temperature and pressure are directly proportional

Mathematically, we have that as:

`\text{ }(P_1)/(T_1)\text{ = }(P_2)/(T_2)`

where:

P1 is the initial pressure which is 65 KPa

P2 is the final pressure that we want to calculate

T1 is the initial temperature which we will convert to Kelvin by adding 273K:

We have T1 as 29 + 273 = 302K

T2 is the final temperature which is also 167 + 273 = 440K

Substituting the values, we have it that:

`\begin{gathered} (65)/(302)\text{ = }(P_2)/(440) \\ \\ P_2\text{ = }(440*65)/(302)\text{ = 94.70 kPa} \end{gathered}`