Question

How many grams of H2SO4 (MW 98) are in 750 mL of 3N H2SO4

Answer 1

To find the grams of H2SO4 in 750 mL of 3N H2SO4, calculate the number of equivalents (2250 meq), convert to moles (2.25 moles), and then multiply by the molar mass (98 g/mole) to get 220.5 grams of H2SO4.

Step-by-step explanation:

To calculate how many grams of H2SO4 are in 750 mL of 3N H2SO4, we need to consider the concept of normality and the molar mass of H2SO4. Normality (N) is a measure of concentration that is equivalent to molarity multiplied by the number of equivalents per mole of the substance. In the case of sulfuric acid (H2SO4), there are two equivalents per mole because it can donate two protons (H+).

To find the mass of H2SO4, we can perform the following steps:

1. Calculate the number of equivalents of H2SO4 in the solution using the volume and normality: (750 mL) x (3 meq/mL) = 2250 meq.
2. Convert milliequivalents to moles: 2250 meq / 1000 = 2.25 moles (since 1 eq of H2SO4 = 0.5 mole of H2SO4).
3. Use the molar mass of H2SO4 to find the mass: 2.25 moles x 98 g/mole = 220.5 grams of H2SO4.

Therefore, 750 mL of 3N H2SO4 contains 220.5 grams of H2SO4.