Question

How many mL of 30% bovine albumin are needed to make 6 mL of a 10% albumin solution?

a 1
b 2
c 3
d 4

Answer 1

To make 6 mL of a 10% albumin solution from a 30% albumin solution, you need 2 mL of the 30% solution. This is calculated using the dilution formula C1V1 = C2V2.

Step-by-step explanation:

To solve this problem, we can use the concept of dilution, which involves reducing the concentration of a solution by adding solvent. In this case, we want to dilute a 30% bovine albumin solution to obtain 6 mL of a 10% albumin solution.

We can use the formula C1V1 = C2V2, where C1 and V1 are the concentration and volume of the initial solution, and C2 and V2 are the concentration and volume of the final solution.

1. First, plug in the values: (30%)(V1) = (10%)(6 mL).
2. Next, solve for V1: V1 = (10% × 6 mL) / 30% = 2 mL.
3. Therefore, you would need 2 mL of the 30% bovine albumin to make 6 mL of a 10% solution.

The correct answer is b. 2 mL of 30% bovine albumin are needed.