Question

A cholesterol QC chart has the following data for the normal control: Mean = 137 mg/dL 2SD = 6 mg/dL N=14 Calculate the coefficient of variation (CV) for the control is: (QMA-16).

a) 1.14%
b) 2.19%
c) 4.38%
d) 9.49%

Answer 1

The coefficient of variation (CV) for the control is approximately 4.38%.

Step-by-step explanation:

To calculate the coefficient of variation (CV), divide the standard deviation (2SD) by the mean (M) and multiply by 100. In this case, the standard deviation is 6 mg/dL and the mean is 137 mg/dL. So, the CV = (6/137) x 100 ≈ 4.38%. Therefore, option c) 4.38% is the correct answer.