Question

A 2% saline erythrocyte suspension contains how many mL of packed erythrocytes per 5 mL of isotonic saline solution?

a 0.1
b 0.2
c 0.5
d 1.0

Answer 1

The answer is 0.1 mL of packed erythrocytes per 5 mL of isotonic saline solution. So, the correct answer is option a) 0.1.

A 2% saline erythrocyte suspension means that there are 2 grams of erythrocytes in 100 mL of solution.

To find out how many mL of packed erythrocytes are in 5 mL of isotonic saline solution, we need to calculate the amount of erythrocytes in 5 mL of the suspension.

First, we need to convert the percentage to grams. Since 2% means 2 grams per 100 mL, we can calculate the amount of erythrocytes in 5 mL using the following equation:

(2 grams / 100 mL) x 5 mL = 0.1 grams

Therefore, there are 0.1 grams of packed erythrocytes in 5 mL of the isotonic saline solution.

Now, we need to convert grams to milliliters. The density of erythrocytes is approximately 1 g/mL. So, 0.1 grams of erythrocytes is equal to 0.1 mL.

Answer 2

In a 2% saline erythrocyte suspension, there are 0.1 mL of packed erythrocytes per 5 mL of isotonic saline solution.

Step-by-step explanation:

A 2% saline erythrocyte suspension would suggest that in every 100 mL of solution, there are 2 mL of packed red blood cells (erythrocytes). Therefore, in a smaller volume such as 5 mL of solution, one would calculate the volume of erythrocytes using direct proportion.

Here's the calculation:

• (2 mL erythrocytes / 100 mL solution) = (x mL erythrocytes / 5 mL solution)
• x = (2 mL / 100 mL) × 5 mL
• x = 0.1 mL erythrocytes

So for every 5 mL of isotonic saline solution, there are 0.1 mL of packed erythrocytes.