Answer:
0.74 g O
3
=
48
0.74
=0.0154 mol O
3
0.67 g NO=
30
0.67
=0.0223 mol NO
O
3
is the limiting reagent and NO is in excess =0.0223−0.0154=0.007 mol
Thus, O
3
taken =NO
2
formed =0.0154 mol NO
2
=0.0154×46 g NO
2
Step-by-step explanation: