Final answer:
NaOH (base₅) would favor the formation of the Hoffman product in an E2 reaction.
Step-by-step explanation:
The base that would favor the formation of the Hoffman product in an E2 reaction is base₅, which is NaOH. In an E2 reaction, the formation of the Hoffman product is favored by sterically hindered and strong bases. NaOH is a relatively strong base compared to the other options, and it is not sterically hindered. This makes it more likely to favor the formation of the Hoffman product in an E2 reaction.