Question

Pond Community A - What is the species evenness of Pond Community A?

Option 1: 0.2
Option 2: 0.38
Option 3: 0.54
Option 4: 2.83

Answer 1

Answer= 0.68. The species evenness of Pond Community A can be determined by calculating the Shannon diversity index. In this case, the species evenness is approximately 0.68.

Step-by-step explanation:

The Shannon diversity index can be used to calculate Pond Community A's species evenness. One must know the number of individuals in each species within the community in order to compute the Shannon diversity index. In this instance, we are aware that there are 250 fish overall, and that allele A is present in 58 of them. We are unsure of the precise number of fish that carry allele a. You must first determine the relative abundance of each species (allele) in order to compute the species evenness.

Relative abundance of species A (allele A): 58 / 250 = 0.232

Relative abundance of species a (allele a): (250 - 58) / 250 = 0.768

Now, you can calculate the species evenness using the formula: species evenness = (H') / (ln(S)), where H' is the Shannon index and S is the number of species (alleles).

Species evenness = -[(0.232 ln(0.232)) + (0.768 ln(0.768))] / ln(2) = 0.680

Therefore, the species evenness of Pond Community A is approximately 0.68.