Question

Assuming 1-hot logic and that all or gates are the same number of inputs, what would be the largest or gate needed to represent any of the output bits? a. The largest OR gate needed to represent any output bit would have 2ⁿ inputs, where n is the number of input bits.

b. The largest OR gate needed to represent any output bit would have n inputs, where n is the number of input bits.
c. The largest OR gate needed to represent any output bit would have 2^(n-1) inputs, where n is the number of input bits.
d. The largest OR gate needed to represent any output bit would have 2n inputs, where n is the number of input bits.

Answer 1

In 1-hot logic, the largest OR gate needed for any output bit would have the same number of inputs as there are input bits, which is option b.

Step-by-step explanation:

When using 1-hot logic, where only one input is high (1) at a time and all others are low (0), the largest OR gate needed to represent any output bit is determined by the number of unique combinations of inputs that can occur. Since 1-hot logic suggests that for n input bits, there can only be n unique true conditions (because only one input can be high at a time), the largest OR gate you would need would have n inputs.

Therefore, the correct answer is b. The largest OR gate needed to represent any output bit would have n inputs, where n is the number of input bits. This is because each output bit will represent one unique condition of the inputs being high, which directly corresponds to the number of input bits.

The largest OR gate needed to represent any output bit would have 2n inputs, where n is the number of input bits.

For example, if we have 3 input bits, the largest OR gate needed would have 23 = 8 inputs.

This is because in 1-hot logic, each input bit is represented by a separate OR gate, and there are n input bits. Each input bit has two possible values (0 or 1), so the number of inputs needed for the largest OR gate is 2n.