Final answer:
To calculate the energy a photon absorbs, use the equation E = hv, where E is energy, h is Planck's constant, and v is the frequency. Planck's constant is 6.626 × 10^-34 joule-seconds, and frequency is measured in hertz. The energy can also be related to photon wavelength with E = hc/λ, where c is the speed of light.
Step-by-step explanation:
To calculate the energy absorbed by a photon, we use the equation E = hv, where E stands for energy, h is Planck's constant, and v is the frequency of the photon. Planck's constant, h, is a fundamental physical constant with the value of 6.626 × 10-34 joule-seconds (J·s). Frequency, denoted by v, is the number of cycles of the wave that pass a point per second, measured in hertz (Hz).
Additionally, the energy of a photon can also be expressed in relation to its wavelength λ by using the equation E = hc/λ, where c is the speed of light (approximately 3.00 x 108 meters per second). When working with small systems like individual photons, energy might be expressed in electron volts (eV), a common unit in atomic and nuclear physics.
The energy absorbed by an object can be calculated using the equation E = hv, where E represents energy, h is Planck's constant, and v is the frequency.