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Suppose a 87.5-kg sprinter accelerates from rest to 11 m/s in 2.8 s. What is the sprinter's acceleration?

a) 1.25 m/s²
b) 3.93 m/s²
c) 7.86 m/s²
d) 11 m/s²

User DarrenMB
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1 Answer

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Final answer:

The sprinter's acceleration is calculated by dividing the change in velocity by the time taken. With a final velocity of 11 m/s and a time of 2.8 seconds from rest, the acceleration is 3.93 m/s².

Step-by-step explanation:

To find the sprinter's acceleration, we use the following formula: a = (Δv)/(Δt). Where a is acceleration, Δv is the change in velocity, and Δt is the change in time. In this case, the sprinter accelerates from rest (initial velocity, vi = 0 m/s) to a final velocity (vf = 11 m/s) in 2.8 seconds. Using the formula: a = (vf - vi)/(Δt) = (11 m/s - 0 m/s)/(2.8 s) = 11 m/s / 2.8 s = 3.93 m/s². Therefore, the sprinter's acceleration is 3.93 m/s², which corresponds to option b) is the right answer.

User Phil Evans
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