Final answer:
The question seeks to determine the number of standard drink equivalents in a 60-ounce pitcher of beer. A standard drink is approximately 12 ounces of 5% ABV beer, hence a 60-ounce pitcher would contain 5 standard drink equivalents. The multiple-choice options provided do not include the correct answer.
Step-by-step explanation:
The question is asking to find out how many standard drink equivalents are contained within a 60-ounce pitcher of beer. In the United States, one standard drink contains approximately 14 grams of pure alcohol. This usually translates to 12 ounces of beer, assuming the beer is about 5% alcohol by volume (ABV). Therefore, to calculate the number of standard drinks in a 60-ounce pitcher, you need to divide 60 by 12, which gives you 5.
The correct answer to the question is not listed among the provided options (a, b, c, d), since each of these options underestimates the number of standard drinks in a 60-ounce pitcher of beer. With this information, we can say that a 60-ounce pitcher contains 5 standard drink equivalents, which means none of the given choices are correct.