Question

Walter has 124 bills consisting 5-dollar bills and 10-dollar bills. If Walter has $840, how many of each kind of bill does he have?

Answer 1

To find the number of each kind of bill, we can set up a system of equations. By multiplying and subtracting the equations, we can find the solution.

Walter has 80 $5 bills and 44 $10 bills.

Step-by-step explanation:

Let's say the number of $5 bills is x and the number of $10 bills is y.

Then we can set up the following equations:

x + y = 124 (equation 1)

5x + 10y = 840 (equation 2)

We can solve this system of equations by either substitution or elimination method.

Let's use the elimination method.

Multiply equation 1 by 5 to make the coefficients of x the same in both equations:

5x + 5y = 620 (equation 3)

Subtract equation 3 from equation 2:

5x + 10y - (5x + 5y) = 840 - 620

5y = 220

y = 44

Substitute y = 44 into equation 1:

x + 44 = 124

x = 80

Therefore, Walter has 80 $5 bills and 44 $10 bills.