Question

Can I please get help with question 1 practice questions

Answer 1

Given:

Line pass through ( 3, 4)

Parallel to the,

`y=-(2)/(3)x+1`

Find-:

The equation of a line.

Explanation-:

The slope of the parallel line is also the same.

`m_1=m_2`

Where

m is the slope of a parallel line

The general equation of a line is:

`y=mx+c`

So the equation become is:

`\begin{gathered} y=mx+c \\ \\ y=-(2)/(3)x+c \end{gathered}`

The line pass ( 3,4)

That mean,

`(x,y)=(3,4)`
`\begin{gathered} y=-(2)/(3)x+c \\ \\ (x,y)=(3,4) \\ \\ 4=-(2)/(3)(3)+c \\ \\ 4=-2+c \\ \\ c=4+2 \\ \\ c=6 \end{gathered}`

So the equation of a line is:

`\begin{gathered} y=-(2)/(3)x+6 \\ \\ y=(-2x)/(3)+(18)/(3) \\ \\ y=(-2x+18)/(3) \\ \\ 3y=-2x+18 \\ \\ 2x+3y=18 \end{gathered}`