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Can I please get help with question 1 practice questions

Can I please get help with question 1 practice questions-example-1
User Trqhien
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1 Answer

29 votes
29 votes

Given:

Line pass through ( 3, 4)

Parallel to the,


y=-(2)/(3)x+1

Find-:

The equation of a line.

Explanation-:

The slope of the parallel line is also the same.


m_1=m_2

Where

m is the slope of a parallel line

The general equation of a line is:


y=mx+c

So the equation become is:


\begin{gathered} y=mx+c \\ \\ y=-(2)/(3)x+c \end{gathered}

The line pass ( 3,4)

That mean,


(x,y)=(3,4)
\begin{gathered} y=-(2)/(3)x+c \\ \\ (x,y)=(3,4) \\ \\ 4=-(2)/(3)(3)+c \\ \\ 4=-2+c \\ \\ c=4+2 \\ \\ c=6 \end{gathered}

So the equation of a line is:


\begin{gathered} y=-(2)/(3)x+6 \\ \\ y=(-2x)/(3)+(18)/(3) \\ \\ y=(-2x+18)/(3) \\ \\ 3y=-2x+18 \\ \\ 2x+3y=18 \end{gathered}

User Axemasta
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