Question

A bag contains 6 apples and 4 bananas. If two fruits are drawn one by one with replacement, find the probability that the first one is an apple and the second one is banana.

Answer 1

we have

probability first one is an apple:

`(6)/(6+4)=(6)/(10)`

probability the second one is banana:

`(4)/(6+4)=(4)/(10)`

therefore, the probability that the first one is an apple and the second one is banana:

`(6)/(10)*(4)/(10)=(24)/(100)=(6)/(25)`

answer: 6/25