Final answer:
The valid host on the network 192.168.24 /29 is 192.168.24.1.
Step-by-step explanation:
The given network address is 192.168.24 /29. This means that the network address is 192.168.24.0 and the subnet mask is 255.255.255.248. With a subnet mask of 255.255.255.248, the last 3 bits in the fourth octet (192.168.24.x) are used for host addresses.
Checking the options:
- Option 1: 192.168.24.1 - This is a valid host address within the given network since it falls within the range of 192.168.24.1 to 192.168.24.6.
- Option 2: 192.168.24.7 - This is not a valid host address. The last bit in the fourth octet is set to 1, which is reserved for the broadcast address.
- Option 3: 192.168.25.3 - This is not a valid host address. The network address is 192.168.25, which is different from the given network address of 192.168.24.
- Option 4: 192.168.23.8 - This is not a valid host address. The network address is 192.168.23, which is different from the given network address of 192.168.24.
Therefore, the valid host on the network 192.168.24 /29 is 192.168.24.1.