Question

a steel rod AB Length 140cm long is balanced in the laboratory, with Sharp edge support at both and Cd 20cm away from the end. If two was upward force 40n was placed away from it and B the steel rod have weight of 120n a 1000 thread of 3ON was placed 40cm from A Similarities 80n Load was placed 55cm from B. Find the reaction at both support.​

Answer 1

The reaction at support A is 160N and the reaction at support B is 200N.

Step-by-step explanation:

To find the reactions at both supports for the steel rod, we need to analyze the forces acting on the rod and apply the principle of equilibrium. Let's consider the forces acting on the rod:

• Weight of the steel rod (120N) acting downwards at the center of the rod.
• Upward force (40N) placed 40cm away from point B.
• Load of 80N placed 55cm away from point B.

Since the rod is balanced, the sum of the forces acting vertically must be zero. Using this information, we can calculate the reactions at both supports:

1. Reaction at point A = Sum of vertical forces = Weight of the rod + Upward force = 120N + 40N = 160N
2. Reaction at point B = Sum of vertical forces = Weight of the rod + Load = 120N + 80N = 200N