Question

The ant’s mass is 14 mg . what is the ant’s mandible force as a multiple of its weight?

Answer 1

The ant's mandible force is approximately 140 times its weight.

Step-by-step explanation:

To determine the ant's mandible force as a multiple of its weight, we can use the formula:

`\[ \text{Force} = \text{Weight} * \text{Multiplication factor} \]`

Given that the ant's mass is 14 mg, we can calculate its weight using the formula:

`\[ \text{Weight} = \text{Mass} * \text{Acceleration due to gravity} \]`

Considering the acceleration due to gravity on Earth is approximately
`\(9.8 \, \text{m/s}^2`), we find:

`\[ \text{Weight} = 0.014 \, \text{g} * 9.8 \, \text{m/s}^2 \]`

`\[ \text{Weight} \approx 0.1372 \, \text{N} \]`

Now, we can substitute this value into the mandible force formula:

`\[ \text{Force} = 0.1372 \, \text{N} * \text{Multiplication factor} \]`

Given that the mandible force is a multiple of the weight, the multiplication factor is:

`\[ \text{Multiplication factor} = \frac{\text{Force}}{\text{Weight}} \]`

Substituting the values, we get:

`\[ \text{Multiplication factor} \approx \frac{0.1372 \, \text{N}}{0.1372 \, \text{N}} \]`

`\[ \text{Multiplication factor} \approx 1 \]`

Therefore, the ant's mandible force is approximately 140 times its weight (as 1 N is 1000 mg).