Final answer:
To prepare a 1.0-mg/ml solution from a 13.4-mg/ml solution, the analyst can use the concentration equation C1V1 = C2V2 and perform a serial dilution by measuring out 0.746 ml of the stock solution and adding enough solvent to reach a final volume of 10 ml.
Step-by-step explanation:
To prepare a 1.0-mg/ml solution from a 13.4-mg/ml solution, the analyst would perform a serial dilution.
A serial dilution involves diluting a concentrated stock solution stepwise to achieve the desired concentration. To dilute the 13.4-mg/ml solution to 1.0-mg/ml, the analyst could use the concentration equation C1V1 = C2V2, where C1 and V1 represent the concentration and volume of the original solution, and C2 and V2 represent the concentration and volume of the final diluted solution.
Using the equation:
- C1 = 13.4 mg/ml (original concentration)
- C2 = 1.0 mg/ml (desired concentration)
- V1 = Volume of stock solution needed
- V2 = Final volume required
To calculate V1:
V1 = (C2 × V2) / C1
Let's assume that we want to end up with 10 ml of the final 1.0-mg/ml solution:
V2 = 10 ml
So:
V1 = (1.0 mg/ml × 10 ml) / 13.4 mg/ml = 0.746 ml
The analyst would measure out 0.746 ml of the 13.4-mg/ml stock solution and add enough solvent to reach a final volume of 10 ml. This would yield a solution with a concentration of 1.0 mg/ml. If necessary, multiple serial dilutions could be performed to reach progressively lower concentrations.