Question

Two cars leave winnipeg at 9 a.m. In the same direction on the same road. Once dad averages 70 km/h while the other averages 90 km/h. At what time will they by 70 km apart?

Answer 1

12:30

Step-by-step explanation:

First let's review the information (important information is bolded and the question in basic words is italicised and underlined)

• 2 cars leave
• Winnipeg
• left at 9 a.m.
• same direction
• same road
• car a = 70 km/h
• car b = 90 km/h
• time when car a-------car b are 70 km apart

Now the expression (a math problem written out in mathematical format without a solution) is (the solved version is underneath the expression)

70÷(90-70)

= 70÷20

= 3.5 hrs

= 9 am + 3 hrs + 30 mins

= 12 am + 30 mins

= 12:30

I hope this helps you.

Answer 2

The two cars that leave Winnipeg at 9 a.m., one averaging 70 km/h and the other 90 km/h, will be 70 km apart at 12:30 p.m.

Step-by-step explanation:

To calculate at what time two cars leaving Winnipeg at 9 a.m. will be 70 km apart when traveling in the same direction, one needs to determine how long it will take for the distance between them to increase to 70 km based on the difference in their speeds. One car averages 70 km/h and the other 90 km/h. The difference in speed between the two cars is 20 km/h (90 km/h - 70 km/h).

To find the time it takes for the separation to be exactly 70 km, we use the formula:

Time = Distance / Speed Difference

Plugging in the values we have:

Time = 70 km / 20 km/h = 3.5 hours

Since they left at 9 a.m., we add 3.5 hours to this time to determine when they will be 70 km apart.

9 a.m. + 3.5 hours = 12:30 p.m.

Therefore, the two cars will be 70 km apart at 12:30 p.m..