Question

Does invoking Long.MAX_VALUE + 1 result in an exception?

Answer 1

Invoking Long.MAX_VALUE + 1 does not throw an exception; it causes an overflow and results in Long.MIN_VALUE due to two's complement arithmetic.

Step-by-step explanation:

When you invoke Long.MAX_VALUE + 1 in Java, it does not result in an exception. Instead, due to integer overflow, the result wraps around to the negative side of the range and ends up being Long.MIN_VALUE.

This is because Java uses two's complement arithmetic for integer operations, which means that when a calculation exceeds the maximum value that can be stored in the variable (in this case, Long.MAX_VALUE), it goes around to the smallest (negative) value and continues from there.