Question

The heat combustion of glucose is 2800 kJ/mol. A sample of glucose (C6H12O6) weighing 5 g was burned with excess oxygen in the bomb calorimeter. The temperature of the bomb rose 2.4 C. What is the heat capacity of the calorimeter? a 4.4 gram sample of Propane (C3H8) was then burned with excess oxygen in the same bomb calorimeter. The temperature of the bomb rose 6.85 C. Calculate Delta E Combustion of propane.

Answer 1

To determine the calorimeter's heat capacity, we use the combustion of glucose and apply the formula q = m x C x ΔT. After finding the heat capacity, we calculate ΔE_combustion for propane using the heat capacity and the new temperature change.

Step-by-step explanation:

To calculate the heat capacity of the calorimeter using the data from burning glucose, we use the formula:

q = m × C × ΔT

Where:

• q is the heat absorbed or released,
• m is the mass of the substance,
• C is the heat capacity of the calorimeter,
• ΔT is the change in temperature.

Given the heat of combustion of glucose is 2800 kJ/mol and the mass burned was 5 g, we convert the mass to moles and use the ΔT given to find:

C = q / (ΔT × number of moles)

For propane, after finding the heat capacity, we can calculate the change in internal energy (ΔE_combustion) by using the formula:

q = C × ΔT

By plugging in the values for C and the ΔT obtained from burning propane, we can find out the ΔE_combustion.