11.2k views
0 votes
Analysis. Let's call the first and the second tanks A and B. Treating air as an ideal gas, the volume of the second tank and the mass of air in the first tank are determined to be 1.326 m3.

a) Use the ideal gas law
b) Apply Boyle's law
c) Employ Charles's law
d) Implement Avogadro's law

User Doletha
by
7.6k points

1 Answer

4 votes

Final answer:

The student is asked to analyze gases in tanks A and B using various gas laws. They are prompted to calculate the number of moles of gas in each tank, determine the final volumes and temperatures of the gases, and find the value of the heat added to one of the tanks. They can use the ideal gas law, Boyle's law, Charles's law, and Avogadro's law to answer these questions.

Step-by-step explanation:

The student is asked to analyze the first and second tanks, which we will call A and B, treating air as an ideal gas. The student is then prompted to use the ideal gas law, Boyle's law, Charles's law, and Avogadro's law to determine various properties of the gases in the tanks.



a) To calculate the number of moles of gas in each compartment, we can use the ideal gas law, which states that PV = nRT. Rearranging the equation, we have n = PV/RT. Given that the initial volume (V), pressure (P), temperature (T), and gas constant (R) are known, we can plug in these values to calculate the number of moles of gas in each compartment.



b) The question asks about the final volume of both gases A and B after heat Q is slowly added to A and B is compressed until both gases reach a pressure of 3.0 atm. Since the compression of B is adiabatic, we can determine the final volume by using the equation P₁V₁^=P₂V₂^, where the exponent equals Cp/Cv.



c) To find the final temperature of gases A and B, we can use the ideal gas law again, with the known values of pressure (3.0 atm), volume (from part b), number of moles (from part a), and gas constant. Rearranging the equation, we have T = PV/nR.



d) The value of Q, the heat added to compartment A, can be determined using the first law of thermodynamics, which states that the change in internal energy is equal to the heat added to the system minus the work done by the system, ∆U = Q - W. Since the piston is frictionless, no work is done, so ∆U = Q. We can then substitute the value of ∆U into the equation and solve for Q.

User Mehran Khan
by
7.6k points