Question

Estimate the rate of the reaction,

H+(aq) + OH-(aq) → H_2O(l)
given that the rate law for the reaction is
rate = (1.3 x 1011 L mol-1 s-1)OH-H+ for neutral water,
where H+ = 1.0 x 10-6 M and OH- = 1.0 x 10-8 M.
(Express your answer in units of mol L-1 s-1.)

Answer 1

The rate of the reaction H+(aq) + OH-(aq) → H2O(l) is 1.3 x 10^-3 mol L^-1 s^-1 when using the given rate law and the concentrations of H+ and OH- for neutral water.

Step-by-step explanation:

To estimate the rate of the reaction H+(aq) + OH-(aq) → H2O(l), we use the provided rate law and the concentrations of H+ and OH- for neutral water. Given the rate law is rate = (1.3 x 1011 L mol-1 s-1)[OH-][H+], and the concentrations are [H+] = 1.0 x 10-6 M and [OH-] = 1.0 x 10-8 M, we can calculate the rate as follows:

rate = (1.3 x 1011 L mol-1 s-1)(1.0 x 10-6 M)(1.0 x 10-8 M)

rate = 1.3 x 10-3 mol L-1 s-1

Therefore, the rate of the reaction is 1.3 x 10-3 mol L-1 s-1.